Using the method introduced in Question 24, find the solutions of the following initial-value problems: Data from

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Using the method introduced in Question 24, find the solutions of the following initial-value problems:

dx (a) + k- dr (b) dx dt (d) (c) (t + 4) dx dt d.x dt dx dt dx dr = t, x(0) = 0, e-kt, x(0) = 0, dx dt - + 4x


Data from Question 24

Show that by making the substitution

V = d.x dt the equation dx dt ap + dx dt may be expressed as = 1 - + v = 1 dt

Show that the solution of this equation is v = 1 + Ce–t and hence find x(t). This technique is a standard method for solving second-order differential equations in which the dependent variable itself does not appear explicitly. Apply the same method to obtain the solutions of the differential equations

dx d.x (a) = 4 dt dt (b) dx dt dx (c) t- d.x dt +e-1 dt dt el = 2dx = 1

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