A capacitor for which (mathrm{C}=10 mathrm{mF}) is connected across an AC source. The source emf is given

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A capacitor for which \(\mathrm{C}=10 \mathrm{mF}\) is connected across an AC source. The source emf is given by \(\mathscr{E}=\mathscr{E}_{\max } \sin \omega t\), with \(\varepsilon_{\max }=5.0 \mathrm{~V}\) and \(\omega=20 \mathrm{~s}^{-1}\).

(a) What is the amplitude of the current through the capacitor?

(b) How does the current amplitude change as you increase the source angular frequency?

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