A proton moves at (6.67 times 10^{5} mathrm{~m} / mathrm{s}) undeflected in the (+x) direction through a
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A proton moves at \(6.67 \times 10^{5} \mathrm{~m} / \mathrm{s}\) undeflected in the \(+x\) direction through a velocity selector, a device containing crossed electric and magnetic fields. You measure the electric field to be \(2.0 \times 10^{5} \mathrm{~N} / \mathrm{C}\) in the positive \(z\) direction.
(a) What are the magnitude and direction of the magnetic field \(\vec{B}\) ?
(b) If the proton's speed doubles, in which direction is it deflected?
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Proton Motion in a Velocity Selector We can analyze the protons motion in the velocity selector usin...View the full answer
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