An electron moves in a straight line at a speed of (6.0 times 10^{7} mathrm{~m} / mathrm{s}).
Question:
An electron moves in a straight line at a speed of \(6.0 \times 10^{7} \mathrm{~m} / \mathrm{s}\). Calculate the magnitude and direction of the magnetic field at a position \(5.0 \mathrm{~mm}\) behind the electron and \(15 \mathrm{~mm}\) below its line of motion.
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Step by Step Answer:
To calculate the magnitude and direction of the magnetic field at the given position we can use the righthand rule for determining the direction of th...View the full answer
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