An (R L C) series circuit has (X_{C}=X_{L}=R). When the circuit is operating at resonance, the current

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An \(R L C\) series circuit has \(X_{C}=X_{L}=R\). When the circuit is operating at resonance, the current amplitude is 1. 0 A. When the angular frequency of the current is doubled, what is the new current amplitude?

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