The motion of a particle in the (x) direction can be described by the equation (x(t)=b t^{2}+c
Question:
The motion of a particle in the \(x\) direction can be described by the equation \(x(t)=b t^{2}+c t+d\), where \(b=0.35 \mathrm{~m} / \mathrm{s}^{2}, c=6.0 \mathrm{~m} / \mathrm{s}\), and \(d=30 \mathrm{~m}\).
(a) What is the particle's acceleration at \(t=10 \mathrm{~s}\) ?
(b) What is its velocity at that instant?
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To find the particles acceleration at t 10 texts we need to differen...View the full answer
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