The position of a particle undergoing simple harmonic motion is given by (x(t)=a cos (b t+pi /
Question:
The position of a particle undergoing simple harmonic motion is given by \(x(t)=a \cos (b t+\pi / 3)\), where \(a=8.00 \mathrm{~m}\) and \(b=2.00 \mathrm{~s}^{-1}\). What are the
(a) amplitude,
(b) frequency \(f\),
(c) period?
(d) What are the speed and acceleration magnitude of the particle at \(t=\pi / 2 \mathrm{~s}\) ?
(e) What is its maximum acceleration magnitude, and at what instant after \(t=0\) does the particle first have this acceleration?
(f) What is its maximum speed, and at what instant after \(t=0\) does it first have this speed?
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