To a vessel that contains \(1.00 \mathrm{~mol}\) of monatomic ideal gas \(\mathrm{A}\) is added \(0.100 \mathrm{~mol}\) of monatomic ideal gas \(\mathrm{B}\). The mass of each atom of gas A is \(3.35 \times 10^{-26} \mathrm{~kg}\), and the mass of each atom of gas B is \(1.39 \times 10^{-25} \mathrm{~kg}\). What is the final average speed of the \(\mathrm{A}\) atoms if the final average speed of the B atoms is \(123 \mathrm{~m} / \mathrm{s}\) ?