You cut a slit in a sheet of paper and use it to produce a diffraction pattern on a screen \(2 \mathrm{~m}\) away from the slit. If, using a laser of wavelength \(543.5 \mathrm{~nm}\), you measure a separation distance of \(4 \mathrm{~mm}\) between the \(n=1\) and \(n=2\) dark fringes of the interference pattern, what is the width of the slit?