In our discussion of blackbody radiation, the average energy of an oscillator E osc = hv/(e hv/kBT
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In our discussion of blackbody radiation, the average energy of an oscillator E̅ osc = hv/(ehv/kBT – 1) was approximated as E̅ osc = hv/[(1 + hv/kBT) − 1] = kBΤ for hv/kBT << 1. Calculate the relative error = (E – E approx )/E in making this approximation for v = 7.50 × 1012 s−1 at temperatures of 5000., 1500., and 300. K. Can you predict what the sign of the relative error will be without a detailed calculation?
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Relative Error E E approx E 00369 for T 5000 K The results for 1500 K and 300 K are 0130 and ...View the full answer
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