Suppose that the electrode potential is set at 1.00 V. The exchange current density is 6.0
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Suppose that the electrode potential is set at 1.00 V. The exchange current density is 6.0 × 10−4 A cm−2 and α = 0.50. Calculate the current density for the ratio of activities a(Fe3+)/a(Fe2+) in the range 0.1 to 10.0 and at 25°C.
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Solution Here we know CFe2 CFe3 05 1 05 The molar ionic conductivity at 25C is given by m...View the full answer
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