Evaluate the surface integral. S y dS, S is the surface z = 2/3 (x 3/2

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Evaluate the surface integral.

ʃʃ_S y dS,
S is the surface z = 2/3 (x^3/2 + y^3/2), 0 < x < 1, 0 < y < 1

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Calculus Early Transcendentals

ISBN: 978-1285741550

8th edition

Authors: James Stewart

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Question Posted: Apr 13, 2019 01:01 PM

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Evaluate the surface integral. S y dS, S is the surface z = 2/3 (x 3/2

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N x2y2 and Sydsx 1 dA So So y x y 1 ...View the full answer

Calculus Early Transcendentals

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