In contrast to the situation of Exercise 40, experiments show that the reaction H 2 + Br

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In contrast to the situation of Exercise 40, experiments show that the reaction H2 + Br2 → 2HBr satisfies the rate law

d[HBr] dt k[H2][Br]/?

and so for this reaction the differential equation becomesdx dt K(а — х)(ь — х)\2

where x = [HBr] and a and b are the initial concentrations of hydrogen and bromine.
(a) Find x as a function of t in the case where a = b. Use the fact that x(0) = 0.
(b) If a > b, find t as a function of x.

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