Solve the initial-value problem. y'' - 6y' + 25y = 0, y(0) = 2, y'(0) = 1
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Solve the initial-value problem.
y'' - 6y' + 25y = 0, y(0) = 2, y'(0) = 1
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The auxiliary equation is r 6r 25 ...View the full answer
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