The function (x) = e x + x, being differentiable and one-to-one, has a differentiable inverse
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The function ƒ(x) = ex + x, being differentiable and one-to-one, has a differentiable inverse ƒ-1(x). Find the value of dƒ-1/dx at the point ƒ(ln 2).
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The inverse of x can be found by solving for x in terms of x ex x x 1ex x Taking the derivative of b...View the full answer
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Related Book For
Thomas Calculus Early Transcendentals
ISBN: 9780321884077
13th Edition
Authors: Joel R Hass, Christopher E Heil, Maurice D Weir
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