The inequality sec x 1 + (x 2 /2) holds on (-/2, /2). Use it to
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The inequality sec x ≥ 1 + (x2/2) holds on (-π/2, π/2). Use it to find a lower bound for the value of ∫01 sec x dx.
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We have the inequality sec x 1 x22 Integrating both ...View the full answer
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Related Book For
Thomas Calculus Early Transcendentals
ISBN: 9780321884077
13th Edition
Authors: Joel R Hass, Christopher E Heil, Maurice D Weir
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