Calculate the vector torque on the square loop shown in Figure 8.15 about an origin at A
Question:
(a) A(0, 0, 0) and B = 100ay mT;
(b) A(0, 0, 0) and B = 200ax + 100ay mT;
(c) A(1, 2, 3) and B = 200ax + 100ay 300az mT;
(d) A(1, 2, 3) and B = 200ax + 100ay 300az mT for x ¥ 2 and B = 0 elsewhere.
Transcribed Image Text:
+2, 2, 0) +2,-2, 0) 0.6 A (2,–2, 0) (2, 2, 0) х
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a The field is uniform and so does not produce any translation of the loop Therefore we may use T IS ...View the full answer
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