Note that from (10.116) and (10.122) that the 10% out-of-band power RF bandwidth for QPSK is where
Question:
where 1/2Tb is the first zero of sinc (2Tbf). From (10.117) we therefore conclude that for M-ary QAM.
Consider a channel of 20-kHz bandwidth. What data rate is supported by QAM for:
(a) M = 4;
(b) M = 16;
(c) M = 64;
(d) M = 256?
Transcribed Image Text:
В 1об = R, Hz = 2 2T, B10% OOB, QPSK 2R, Hz log, M B10% OOB, QAM :2 || (log, M) T,
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Related Book For
Principles of Communications Systems, Modulation and Noise
ISBN: 978-8126556793
7th edition
Authors: Rodger E. Ziemer, William H. Tranter
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