Consider the system shown in Figure P10.44 with m ₁ = 20.0kg, m ₂ = 12.5kg, R=0.200 m, and the mass of the uniform pulley M=5.00kg. Object m ₂ is resting on the floor, and object m ₁ is 4.00 m above the floor when it is released from rest. The pulley axis is friction less. The cord is light, doesn't stretch, and does not slip on the pulley. Calculate the time interval required for m ₁ to hit the floor. How would your answer change if the pulley were mass less?

Transcribed Image Text:

M-R m1 m2 M-R m1 m2

Answer rating: 100% (QA)

Applying Newtons Second law for the mass m 1 we get m 1 a m 1 gT 1 1 For second mass m 2 we ... View the full answer