During a cold day, you can warm your hands by rubbing them together.

(a) Assume the coefficient of kinetic friction between your hands is 0.500, the normal force between your hands is 39.0 N, and that you rub them together at an average relative speed of 39.0 cm/s. What is the rate at which mechanical energy is dissipated?

(b) Assume further that the mass of each of your hands is 350 g, the specific heat of your hands is 4.00 kJ/kg·K, and that all the dissipated mechanical energy goes into increasing the temperature of your hands. How long must you rub your hands together to produce a 5.00°C increase in their temperature?

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Given data 0500 F 390 N s 39 cms 039 ms m ... View the full answer