When a solid mixture of MgCO3 and CaCO3 is heated strongly, carbon dioxide gas is given off and a solid mixture of MgO and CaO is obtained.

MgCO3(s)->MgO(s) +CO2(g) CaCO3(s)->CaO(s)+CO2(g)

If a 24.00-g sample of a mixture of MgCO3 and CaCO3 produces 12.00g CO2, then what is the percentage by mass of MgCO3 in the original mixture?

Answer rating: 100% (QA)

Total moles of CO 2 massmolar mass of CO 2 12004401 0272665 mol Let the mass of MgCO ... View the full answer