1. A configuration of charges is shown below. q = 5 nC 0 5 10 x...

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1. A configuration of charges is shown below. q = 5 nC 0 5 10 x (cm) -29 +9 +39 -9 The electric fields due to the charges -2q, +q, +3q, and -q at x = 11 cm are shown below. The direction of the electric field due to a point charge at any point is along the line joining the charge and the point and away from the charge for a positive charge and towards the charge for a negative charge. E 9 E +a E Ex E29 -2a x= 11 cm +39 The electric fields due to -2q at x = 11 cm is in the negative x-direction, and due to -q, +q and +3q is in the positive x-direction. The strength of the field is determined by the charge and the distance between the charge and the point. The net electric field in Part 1 will point in the positive x-direction. (a) Find the total electric field at x=11 cm. Enet= NC 1. A configuration of charges is shown below. q = 5 nC 0 5 10 x (cm) -29 +9 +39 -9 The electric fields due to the charges -2q, +q, +3q, and -q at x = 11 cm are shown below. The direction of the electric field due to a point charge at any point is along the line joining the charge and the point and away from the charge for a positive charge and towards the charge for a negative charge. E 9 E +a E Ex E29 -2a x= 11 cm +39 The electric fields due to -2q at x = 11 cm is in the negative x-direction, and due to -q, +q and +3q is in the positive x-direction. The strength of the field is determined by the charge and the distance between the charge and the point. The net electric field in Part 1 will point in the positive x-direction. (a) Find the total electric field at x=11 cm. Enet= NC