1) An analysis of the simple pendulum shows that the slope of the line on the...
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1) An analysis of the simple pendulum shows that the slope of the line on the second plot with L on the x-axis and T2 on the y-axis should be: slope = 4 m²/g where g is the acceleration due to gravity near the surface of the earth. Solve this equation for g and determine its value from the slope of the line. Find the percent error from the accepted value of 980 cm/s2 using the equation: % error = [[correct value - experimental value|/correct value] x 100 For this data set, the slope of the line is 0.0408 s²/cm, so g = 4n²/0.0408 = 967 cm/s² with a percent error =[1980-9671/980] x 100 = 13% 2) If a one-meter pendulum has a period of two seconds, what should be the length of a pendulum with a length of one second? (Hint: the square of the period is proportional to the length of the pendulum: T2? L.) 1) An analysis of the simple pendulum shows that the slope of the line on the second plot with L on the x-axis and T2 on the y-axis should be: slope = 4 m²/g where g is the acceleration due to gravity near the surface of the earth. Solve this equation for g and determine its value from the slope of the line. Find the percent error from the accepted value of 980 cm/s2 using the equation: % error = [[correct value - experimental value|/correct value] x 100 For this data set, the slope of the line is 0.0408 s²/cm, so g = 4n²/0.0408 = 967 cm/s² with a percent error =[1980-9671/980] x 100 = 13% 2) If a one-meter pendulum has a period of two seconds, what should be the length of a pendulum with a length of one second? (Hint: the square of the period is proportional to the length of the pendulum: T2? L.)
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