1. Show that the equation x+y+z+ sin(xyz) = 0 defines z as a function of x...

 

Transcribed Image Text:

1. Show that the equation x+y+z+ sin(xyz) = 0 defines z as a function of x and y near (0,0,0). 2. Calculate and z near (0,0). Problem 2: z Show that if (a, b) is close to (1,1), then there exists a point (x, y) R such that y+exy = a x+exy b. 1. Show that the equation x+y+z+ sin(xyz) = 0 defines z as a function of x and y near (0,0,0). 2. Calculate and z near (0,0). Problem 2: z Show that if (a, b) is close to (1,1), then there exists a point (x, y) R such that y+exy = a x+exy b.