1) The Natural Frequency of the system, 2) The Value of ki, if the Natural Frequency...

  

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1) The Natural Frequency of the system, 2) The Value of ki, if the Natural Frequency of the system is increased by 30% 3) The Steady State Amplitude of m, in (mm) 4) The Transmitted Force to the Support Shown in (N) 5) Assume the damping of system is 0, i.e.. c=0 and F(t) is replaced by the pulse shown below in the Figure, what is the response of my in millimeters, when t = 25 second to=Q/10, Ft) + Fo Fo= 1500*Q fimm C Support mi For the Vibratory System Shown, if m = 1.1*Q (kg), Jo=120+0.525*Q k= 35000 + 1350*Q C= 1000 + 25*Q Fo= 1500 Q F(t)=Fo cos(cot), m = 2.1*Q (kg m), (N/m), (N s/m) (N), @= 2*Q Excitation Force ot k= 1200*Q k= 5000*Q =0.3m 12=0.7 m Jo m (kg) (rad/s) F(t) K2 (N/m) (N/m) MITTTTTH 1) The Natural Frequency of the system, 2) The Value of ki, if the Natural Frequency of the system is increased by 30% 3) The Steady State Amplitude of m, in (mm) 4) The Transmitted Force to the Support Shown in (N) 5) Assume the damping of system is 0, i.e.. c=0 and F(t) is replaced by the pulse shown below in the Figure, what is the response of my in millimeters, when t = 25 second to=Q/10, Ft) + Fo Fo= 1500*Q fimm C Support mi For the Vibratory System Shown, if m = 1.1*Q (kg), Jo=120+0.525*Q k= 35000 + 1350*Q C= 1000 + 25*Q Fo= 1500 Q F(t)=Fo cos(cot), m = 2.1*Q (kg m), (N/m), (N s/m) (N), @= 2*Q Excitation Force ot k= 1200*Q k= 5000*Q =0.3m 12=0.7 m Jo m (kg) (rad/s) F(t) K2 (N/m) (N/m) MITTTTTH

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The images you provided present a series of problems related to a vibratory system consisting of a massspringdamper model with two masses m1 and m2 springs k1 and k2 a damper c1 and a rotational inert... View the full answer