1. The net weight (in oz.) of a dry bleach product is to be monitored by...

 

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1. The net weight (in oz.) of a dry bleach product is to be monitored by X and R and X and S control charts using a sample size of n = 5. Data for 20 preliminary samples are shown below. For X and R Subgroup Number X, X2 X3 X. UCL3 = X + A¸R %3D 1 12 10 11 15 12 10 16 14 8 CLg = X = %3D 11 12 10 16 14 4 11 14 13 9 LCL = X – A,R 6. 10 12 11 16 UCLR = D4R %3D 12 11 10 14 13 15 10 13 9. 12 %3D1 CLR = R %3D 8. 14 9. 15 14 13 6. 6. 10 13 12 10 LCLR = D3R 10 15 9. 10 13 12 For X and S. 11 10 12 14 16 11 16 13 9. 11 8 Uclg = X + A3Š 12 %3D 13 16 11 13 15 10 15 13 10 12 9. CLg =X = 2i=1 14 15 12 14 8 16 11 16 15 9. 10 14 12 LCLg = X – A,5 17 13 12 10 14 UCLS = B45 %3D 18 15 12 10 11 13 19 14 16 9. 12 10 CLs = 5 = 4i=1 %3D 20 13 9. 12 14 LCLS = B35 %3D 7. 2 3 567 Determine the trial central line and control limits for the X and R (24 points). UCL = %3D CL = LCL = %3D UCLR = CLR = LCLR = Determine the trial central line and control limits for the X and S (24 points). UCL = CL = LCL = UCLS = CLs = %3D LCLS = 1. The net weight (in oz.) of a dry bleach product is to be monitored by X and R and X and S control charts using a sample size of n = 5. Data for 20 preliminary samples are shown below. For X and R Subgroup Number X, X2 X3 X. UCL3 = X + A¸R %3D 1 12 10 11 15 12 10 16 14 8 CLg = X = %3D 11 12 10 16 14 4 11 14 13 9 LCL = X – A,R 6. 10 12 11 16 UCLR = D4R %3D 12 11 10 14 13 15 10 13 9. 12 %3D1 CLR = R %3D 8. 14 9. 15 14 13 6. 6. 10 13 12 10 LCLR = D3R 10 15 9. 10 13 12 For X and S. 11 10 12 14 16 11 16 13 9. 11 8 Uclg = X + A3Š 12 %3D 13 16 11 13 15 10 15 13 10 12 9. CLg =X = 2i=1 14 15 12 14 8 16 11 16 15 9. 10 14 12 LCLg = X – A,5 17 13 12 10 14 UCLS = B45 %3D 18 15 12 10 11 13 19 14 16 9. 12 10 CLs = 5 = 4i=1 %3D 20 13 9. 12 14 LCLS = B35 %3D 7. 2 3 567 Determine the trial central line and control limits for the X and R (24 points). UCL = %3D CL = LCL = %3D UCLR = CLR = LCLR = Determine the trial central line and control limits for the X and S (24 points). UCL = CL = LCL = UCLS = CLs = %3D LCLS =