1. We will denote the value of S xn-1 e dx by G(n). Assume n >...
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1. We will denote the value of S xn-1 e dx by G(n). Assume n > 1. Using calculus, show that G(n+1) is the same as nG(n). 1. We will denote the value of S xn-1 e dx by G(n). Assume n > 1. Using calculus, show that G(n+1) is the same as nG(n).
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A nice problem in calculus Lets use integration by parts to prove that Gn1 nGn Integration by Parts ... View the full answer
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