An excess amount of silver nitrate was added to 2.50 grams of impure barium chloride which...
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An excess amount of silver nitrate was added to 2.50 grams of impure barium chloride which resulted to a silver chloride precipitate. A. What is the mass of the precipitate formed * B. What is the percentage barium chloride in the sample? An excess amount of silver nitrate was added to 2.50 grams of impure barium chloride which resulted to a silver chloride precipitate. A. What is the mass of the precipitate formed * B. What is the percentage barium chloride in the sample?
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A The reaction of silver nitrate and barium chloride can be written as follo... View the full answer
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