16. An IEEE standard 32-bit floating point number is N = -15 x 2E-127 x 1.F,...

 

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16. An IEEE standard 32-bit floating point number is N = -15 x 2E-127 x 1.F, where S is the sign bit, F is the fractional mantissa, and E the biased exponent. a. Convert the decimal number 123.5 into the IEEE format for floating point numbers. b. Convert the decimal number 100.25 into the IEEE format for floating point numbers. C. d. Describe the steps that take place when two IEEE floating point num- bers are added together. You should start with the two packed floating point numbers and end with the packed sum. Perform the subtraction of 123.5 - 100.25 using the two IEEE-format binary floating point numbers you obtained for 123.5 and 100.25 in the first parts of this question. You should begin the calculation with the packed floating point representations of these numbers and end with the packed result. 16. An IEEE standard 32-bit floating point number is N = -15 x 2E-127 x 1.F, where S is the sign bit, F is the fractional mantissa, and E the biased exponent. a. Convert the decimal number 123.5 into the IEEE format for floating point numbers. b. Convert the decimal number 100.25 into the IEEE format for floating point numbers. C. d. Describe the steps that take place when two IEEE floating point num- bers are added together. You should start with the two packed floating point numbers and end with the packed sum. Perform the subtraction of 123.5 - 100.25 using the two IEEE-format binary floating point numbers you obtained for 123.5 and 100.25 in the first parts of this question. You should begin the calculation with the packed floating point representations of these numbers and end with the packed result.

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a Converting 1235 to IEEE floating point format Decimal number 1235 11110111 1 Determine the sign Po... View the full answer