2. Calculate the angular acceleration of the disk. Show all your work for this and subsequent...

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2. Calculate the angular acceleration of the disk. Show all your work for this and subsequent parts. 1. a 2st2 at t = 0.6s, the displacement = 2. s = 0.6m 3. a 2 x 0.6 (0.6)^2 = 2 m/s. 4. Then we convert this to angular acceleration using alpha = a/ r where r is the radius of the wheel 5. r 0.3m, then a = = 6. 6.67 rad/s =2/0.3 = Score: 0/3 3. Use Newton's Second Law for Rotation to calculate the tension in the string. We will assume that the friction forces are negligible. Hint: The mass of the disk is 2.776 kg. T = 0.5 2.776kg 0.3m x 6.67 rad/s^2 = 2.777 N -> ht 0.30000 sec Frame 72 240 fps 0 cm 10 20 30 40 Distance Distance Time Time^2 Cm M y S T s^2 t^2 1 ... 0 0.00 0 0.00 2 1 0.0100 0.1000 0.0100 3 3 0.0300 0.2000 0.0400 + 5 6 7 8 7 0.0700 0.3000 0.0900 12 12 0.120 0.4000 0.160 18 18 0.180 0.5000 0.250 22 27 0.270 0.6000 0.360 36 36 0.360 0.7000 0.490 9 44 0.440 0.8000 0.640 4 5. Use Newton's Second Law (Fnet = ma) to solve for the mass of the apple. Explain how you used Newton's Second Law to solve for mass. Use the equation editor to show your work. You do not need to show minor algebraic steps. Hint: Earlier, you calculated the angular acceleration for the disk. How is this angular acceleration related to the acceleration of the apple? mass of apple = T/(g - a) mass of apple = 2.777 N / (9.81 m/s - 2 m/s) = 0.37 kg 2. Calculate the angular acceleration of the disk. Show all your work for this and subsequent parts. 1. a 2st2 at t = 0.6s, the displacement = 2. s = 0.6m 3. a 2 x 0.6 (0.6)^2 = 2 m/s. 4. Then we convert this to angular acceleration using alpha = a/ r where r is the radius of the wheel 5. r 0.3m, then a = = 6. 6.67 rad/s =2/0.3 = Score: 0/3 3. Use Newton's Second Law for Rotation to calculate the tension in the string. We will assume that the friction forces are negligible. Hint: The mass of the disk is 2.776 kg. T = 0.5 2.776kg 0.3m x 6.67 rad/s^2 = 2.777 N -> ht 0.30000 sec Frame 72 240 fps 0 cm 10 20 30 40 Distance Distance Time Time^2 Cm M y S T s^2 t^2 1 ... 0 0.00 0 0.00 2 1 0.0100 0.1000 0.0100 3 3 0.0300 0.2000 0.0400 + 5 6 7 8 7 0.0700 0.3000 0.0900 12 12 0.120 0.4000 0.160 18 18 0.180 0.5000 0.250 22 27 0.270 0.6000 0.360 36 36 0.360 0.7000 0.490 9 44 0.440 0.8000 0.640 4 5. Use Newton's Second Law (Fnet = ma) to solve for the mass of the apple. Explain how you used Newton's Second Law to solve for mass. Use the equation editor to show your work. You do not need to show minor algebraic steps. Hint: Earlier, you calculated the angular acceleration for the disk. How is this angular acceleration related to the acceleration of the apple? mass of apple = T/(g - a) mass of apple = 2.777 N / (9.81 m/s - 2 m/s) = 0.37 kg