2.1 lb/ft. The A flexible cable suspended between two vertical supports is hanging under its own...

 

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2.1 lb/ft. The A flexible cable suspended between two vertical supports is hanging under its own weight. The weight of a horizontal roadbed is distributed evenly along the x-axis with the density p coordinate system is chosen so that the y-axis passes through the lowest point P and the x-axis is a = 3 ft below P. If the absolute value of tension force in the cable at point P is T = 5, then the initial value problem that governs the shape of the cable is (Use the notation dy/dx for the first derivative) d'y dz y(0) (0) = The solution of this problem is y = y(x), where y(x) 2.1 lb/ft. The A flexible cable suspended between two vertical supports is hanging under its own weight. The weight of a horizontal roadbed is distributed evenly along the x-axis with the density p coordinate system is chosen so that the y-axis passes through the lowest point P and the x-axis is a = 3 ft below P. If the absolute value of tension force in the cable at point P is T = 5, then the initial value problem that governs the shape of the cable is (Use the notation dy/dx for the first derivative) d'y dz y(0) (0) = The solution of this problem is y = y(x), where y(x)