2u y u(x,0) = 0, u(x,0.5) = 200x, and u(0,0.5) = 200y. 2u Given: (x, y)...

 

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2²u Əy² u(x,0) = 0, u(x,0.5) = 200x, and u(0,0.5) = 200y. 2²u Given: (x, y) + (x,y) = 0, 0:0 ≤ y ≤ 0.5 and boundary conditions: u(0,y) = 0, The finite difference equation is: 4 ujj - Ui+1,jui-1,jui,j-1 Ui,j+1 = 0 - Use the FED method to generate the coefficient matrix. Assume intervals in the x- axis and y-axis, n = m = 4. (20) 2²u Əy² u(x,0) = 0, u(x,0.5) = 200x, and u(0,0.5) = 200y. 2²u Given: (x, y) + (x,y) = 0, 0:0 ≤ y ≤ 0.5 and boundary conditions: u(0,y) = 0, The finite difference equation is: 4 ujj - Ui+1,jui-1,jui,j-1 Ui,j+1 = 0 - Use the FED method to generate the coefficient matrix. Assume intervals in the x- axis and y-axis, n = m = 4. (20)

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24 Solo Given x y 23 x y by R 0 y 05 and uo y 0 u x0 0 4x05 200x 40052004 Using the finite differe... View the full answer