[3 points] Let foo and bar be Haskell functions. foo i [] = False foo i...

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[3 points] Let foo and bar be Haskell functions. foo i [] = False foo i (x:xs) |i == x = True | otherwise = foo i xs bar [] = [] bar (x:xs) y | (foo x y) == False = [x] ++ bar xs y | otherwise = bar xs y In the above code segment, the bar function takes two lists as input and returns a list composed of elements belonging to the first input list but not the second input list. the bar function takes two lists as input and returns a list composed of elements which belong to both lists. the bar function takes two lists as input and returns a list that is the concatenation of the two input lists. the function foo reverses an input list. the function foo takes an element and a list as input and returns whether the element is the first item in the list. [3 points] Let foo and bar be Haskell functions. foo i [] = False foo i (x:xs) |i == x = True | otherwise = foo i xs bar [] = [] bar (x:xs) y | (foo x y) == False = [x] ++ bar xs y | otherwise = bar xs y In the above code segment, the bar function takes two lists as input and returns a list composed of elements belonging to the first input list but not the second input list. the bar function takes two lists as input and returns a list composed of elements which belong to both lists. the bar function takes two lists as input and returns a list that is the concatenation of the two input lists. the function foo reverses an input list. the function foo takes an element and a list as input and returns whether the element is the first item in the list.

Answer rating: 100% (QA)

Answer A In the above code segment the bar function ta... View the full answer