5. (20 pts) Assume that x and y are of type int, which is 32 bits....

  

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5. (20 pts) Assume that x and y are of type int, which is 32 bits. Enter the value of (y-x) in decimal. This is the value that would be stored in z if int z = y - x; Consider the instruction: cmpl $eax, 8ecx Fill in the value of the flags if %eax contains x and %ecx contains y. y ZF CF OF 17 -34 -34 X -34 17 -34 Ox7ffffff0 49 Ox7ffffff0 -49 49 49 Ox7ffffff0 -0x7ffffff0 y-x SF 5. (20 pts) Assume that x and y are of type int, which is 32 bits. Enter the value of (y-x) in decimal. This is the value that would be stored in z if int z = y - x; Consider the instruction: cmpl $eax, 8ecx Fill in the value of the flags if %eax contains x and %ecx contains y. y ZF CF OF 17 -34 -34 X -34 17 -34 Ox7ffffff0 49 Ox7ffffff0 -49 49 49 Ox7ffffff0 -0x7ffffff0 y-x SF