A 100 V DC separately excited motor has an armature resistance 0.2 ohms. The field coil...

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A 100 V DC separately excited motor has an armature resistance 0.2 ohms. The field coil has a field resistance of 1Kohm and is excited by a 28 V DC supply. Given that the developed torque by the armature is 30 Nm, demonstrate how you would calculate the armature electrical loss, its speed, developed power of the motor and the output torque if the mechanical loss is 5W. Use the following constant: i) Voltage constant 0.6 V-sec/rad and torque constant 0.6 N-m/A Voltage constant 21.4 v-sec/A rad and torque constant 21.4 N-m/A² ii) A 100 V DC separately excited motor has an armature resistance 0.2 ohms. The field coil has a field resistance of 1Kohm and is excited by a 28 V DC supply. Given that the developed torque by the armature is 30 Nm, demonstrate how you would calculate the armature electrical loss, its speed, developed power of the motor and the output torque if the mechanical loss is 5W. Use the following constant: i) Voltage constant 0.6 V-sec/rad and torque constant 0.6 N-m/A Voltage constant 21.4 v-sec/A rad and torque constant 21.4 N-m/A² ii)

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To calculate the armature electrical loss we need to determine the armature current We can use Ohms ... View the full answer