A 1.20-kg skateboard is coasting along the pavement at a speed of 5.00 m/s when a...

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A 1.20-kg skateboard is coasting along the pavement at a speed of 5.00 m/s when a 0.800- kg cat drops from a tree vertically downward onto the skateboard. What is the speed of the skateboard-cat combination? (Remember that momentum is a vector and that conservation of momentum is a vector equation that is applied separately in x- and y- directions) mc=0.8 kg BEFORE (Ptotal=+6 kg m/s) AFTER V₁=5.0m/s m = 1.2kg ms+mc v'=? A 1.20-kg skateboard is coasting along the pavement at a speed of 5.00 m/s when a 0.800- kg cat drops from a tree vertically downward onto the skateboard. What is the speed of the skateboard-cat combination? (Remember that momentum is a vector and that conservation of momentum is a vector equation that is applied separately in x- and y- directions) mc=0.8 kg BEFORE (Ptotal=+6 kg m/s) AFTER V₁=5.0m/s m = 1.2kg ms+mc v'=?

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to solve this problem using the conservation of momentum principle 1 Separate the ho... View the full answer