A 22.0 m long aluminum cable with a cross-sectional area of 2.01 103 m2 is used

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A 22.0 m long aluminum cable with a cross-sectional area of 2.01 ✕ 10−3 m2 is used to suspend a 3.80 ✕ 103 kg container. By how much will the cable stretch (in m) once bearing the load? (Young's modulus for aluminum is Y = 7.0 ✕ 10¹⁰Pa.)

Related Book For answer-question

Economics

ISBN: 978-0073375694

18th edition

Authors: Campbell R. McConnell, Stanley L. Brue, Sean M. Flynn

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Posted Date: Aug 06, 2021 08:46 AM

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Margin of error = 18.2 cm, standard deviation = 95.2 cm
Margin of error = 0.5 g, standard deviation = 8.7 g
Margin of error = 3.5 ml, standard deviation = 155.2 ml

A 22.0 m long aluminum cable with a cross-sectional area of 2.01 103 m2 is used

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Economics

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