A 6 m long parallel flange IPE 180, I-Profile, is to be simply supported at the...
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A 6 m long parallel flange IPE 180, I-Profile, is to be simply supported at the ends Calculate the magnitude of the distributed load per metre length which the beam can carry if the bending stress is not to exceed 68 MPa Take the mass of the beam into consideration The following formulae may be used: • For a uniform cross section beam with symmetrical loading the maximum bending moment at mid-span will be M W XL 8 where OW total W distributed load + Wweight of the beam o L = the length of the beam xy . I where y = the furthest fibre and I = second moment of the area Solving hints (advice): Solve first in terms of Wtotal and then calculate the Waistributed load A 6 m long parallel flange IPE 180, I-Profile, is to be simply supported at the ends Calculate the magnitude of the distributed load per metre length which the beam can carry if the bending stress is not to exceed 68 MPa Take the mass of the beam into consideration The following formulae may be used: • For a uniform cross section beam with symmetrical loading the maximum bending moment at mid-span will be M W XL 8 where OW total W distributed load + Wweight of the beam o L = the length of the beam xy . I where y = the furthest fibre and I = second moment of the area Solving hints (advice): Solve first in terms of Wtotal and then calculate the Waistributed load A 6 m long parallel flange IPE 180, I-Profile, is to be simply supported at the ends Calculate the magnitude of the distributed load per metre length which the beam can carry if the bending stress is not to exceed 68 MPa Take the mass of the beam into consideration The following formulae may be used: • For a uniform cross section beam with symmetrical loading the maximum bending moment at mid-span will be M W XL 8 where OW total W distributed load + Wweight of the beam o L = the length of the beam xy . I where y = the furthest fibre and I = second moment of the area Solving hints (advice): Solve first in terms of Wtotal and then calculate the Waistributed load A 6 m long parallel flange IPE 180, I-Profile, is to be simply supported at the ends Calculate the magnitude of the distributed load per metre length which the beam can carry if the bending stress is not to exceed 68 MPa Take the mass of the beam into consideration The following formulae may be used: • For a uniform cross section beam with symmetrical loading the maximum bending moment at mid-span will be M W XL 8 where OW total W distributed load + Wweight of the beam o L = the length of the beam xy . I where y = the furthest fibre and I = second moment of the area Solving hints (advice): Solve first in terms of Wtotal and then calculate the Waistributed load
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Given Length of beam L 6 text m Maximum bending stress sigma 68 text MPa Crosssection of beam IPE 18... View the full answer
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