A ball of mass 2.0 kg is rolling on the ground with velocity 0...

 

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A ball of mass 2.0 kg is rolling on the ground with velocity <0,0, 1.5 m/s when you kick it. Your kick delivers an impulse (change in momentum) 4 Ns in the -x direction. The net force on the rolling ball, due to the grass and air, is 2.5 N in the direction opposite to the direction of the ball's momentum. In this problem the y- dimension is a vertical and x-z plane is the locally flatsurface of the earth. Using a time step of 0.5 seconds, find the position of the ball 1 second after you kick it, assuming that the ball is at the origin at the moment it was kicked. HINT: To solve this problem you will need to consider... 1. First, the effect of the kick alone at t = 0. 2. Then, the effect of the force due to the grass and air at t > 0 A ball of mass 2.0 kg is rolling on the ground with velocity <0,0, 1.5 m/s when you kick it. Your kick delivers an impulse (change in momentum) 4 Ns in the -x direction. The net force on the rolling ball, due to the grass and air, is 2.5 N in the direction opposite to the direction of the ball's momentum. In this problem the y- dimension is a vertical and x-z plane is the locally flatsurface of the earth. Using a time step of 0.5 seconds, find the position of the ball 1 second after you kick it, assuming that the ball is at the origin at the moment it was kicked. HINT: To solve this problem you will need to consider... 1. First, the effect of the kick alone at t = 0. 2. Then, the effect of the force due to the grass and air at t > 0

Answer rating: 100% (QA)

Heres how to find the position of the ball 1 second after you kick it 1 Effect of the kick at t 0 Initial momentum of the ballp0 0015 kgms Change in momentum due to the kickp 4 Ns00 negative x due to ... View the full answer