A charge is placed at point O. The electric intensity of point A is 540 NC-....
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A charge is placed at point O. The electric intensity of point A is 540 NC-. The electric potential of point B is 1.8 x 105 V. The distance between A and B is 40 m and B is between O and A, however is closer to A than it is to O. A point mass (20 mg) containing -4 C on it, is initially at rest at A. Then it starts moving from A towards O due to electromagnetic attraction force. a. Find the value of the charge placed at point O. b. Calculate how much work should be done to bring the -4 C from A to B. c. Calculate the velocity of the -4 C charge at point B. A charge is placed at point O. The electric intensity of point A is 540 NC-. The electric potential of point B is 1.8 x 105 V. The distance between A and B is 40 m and B is between O and A, however is closer to A than it is to O. A point mass (20 mg) containing -4 C on it, is initially at rest at A. Then it starts moving from A towards O due to electromagnetic attraction force. a. Find the value of the charge placed at point O. b. Calculate how much work should be done to bring the -4 C from A to B. c. Calculate the velocity of the -4 C charge at point B.
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a To find the value of the charge placed at point O we can use the formula for electric field intensity E k Q r2 where E is the electric field intensi... View the full answer
Related Book For
Physics
ISBN: 978-0077339685
2nd edition
Authors: Alan Giambattista, Betty Richardson, Robert Richardson
Posted Date:
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