A closed cylindrical tank, 3.05m high and 0.610 m diameter has a mercury U-tube gauge connected...

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A closed cylindrical tank, 3.05m high and 0.610 m diameter has a mercury U-tube gauge connected to the side 0.717 m above the bottom of the tank, the other end of the U-tube being open. When the tank is empty the level of mercury is 0.22 m below the bottom of the tank. A piezometer tube is connected to the bottom of the tank. Into the tank are placed in turn, 136 I of glycerine, 181 I of water and 226 I of light oil so that they do not mix. Air is blown in the top to a gauge pressure of 0.192 bar. What will be the difference of mercury level in the U-tube, and the height of fluid surface in the piezometer tube above the tank floor level? (The quantity of liquid in the gauges may be ignored) (0.296 m, 3.002 m) A closed cylindrical tank, 3.05m high and 0.610 m diameter has a mercury U-tube gauge connected to the side 0.717 m above the bottom of the tank, the other end of the U-tube being open. When the tank is empty the level of mercury is 0.22 m below the bottom of the tank. A piezometer tube is connected to the bottom of the tank. Into the tank are placed in turn, 136 I of glycerine, 181 I of water and 226 I of light oil so that they do not mix. Air is blown in the top to a gauge pressure of 0.192 bar. What will be the difference of mercury level in the U-tube, and the height of fluid surface in the piezometer tube above the tank floor level? (The quantity of liquid in the gauges may be ignored) (0.296 m, 3.002 m)

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ANSWER To solve this problem we need to calculate the pressures at different points and then use the hydrostatic equation to find the heights of the f... View the full answer