A coffee company claims that about 78% of university students in the U.S. drink coffee daily....

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A coffee company claims that about 78% of university students in the U.S. drink coffee daily. Suppose we select a random sample of 100 students at Mizzou and use it to compute the sample proportion p, the proportion of the students who drink coffee daily. (A) Why can we conclude that the distribution of from a sample of 100 randomly selected students would follow an approximately normal distribution? [Select] (B) If the true proportion p of all U.S. college students who drink coffee daily is 0.78, find , the standard deviation (also called the standard error) of the distribution of sample proportions, based on a sample size of 100 selected Mizzou students. [Select] (C) Still supposing that the true proportion of all U.S. college students who exercise regularly is 0.78, find the probability that the sample proportion of the 100 randomly selected Mizzou students would be between p = .70, [Select] and p = .75 A coffee company claims that about 78% of university students in the U.S. drink coffee daily. Suppose we select a random sample of 100 students at Mizzou and use it to compute the sample proportion p, the proportion of the students who drink coffee daily. (A) Why can we conclude that the distribution of from a sample of 100 randomly selected students would follow an approximately normal distribution? [Select] (B) If the true proportion p of all U.S. college students who drink coffee daily is 0.78, find , the standard deviation (also called the standard error) of the distribution of sample proportions, based on a sample size of 100 selected Mizzou students. [Select] (C) Still supposing that the true proportion of all U.S. college students who exercise regularly is 0.78, find the probability that the sample proportion of the 100 randomly selected Mizzou students would be between p = .70, [Select] and p = .75