Jared Diamond's geography hypothesis for the advantages of people who inhabited the Eurasian continent could be understood through the lens of an endogenous growth model where the initial stock of technology is higher, representing the greater number of plants and animals capable of being domesticated.

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12. A project manager has compiled a list of major activities that will be required to install a computer information system in her firm. The list includes estimated completion times for activities and precedence relationships. Immediate Activity Predecessor A D E H F G B I J A K D Immediate Activity Predecessor E A F B I J Estimated Times (weeks) 2-4-6 6-8-10 7-9-12 2-3-5 3-4-8 5-7-9 Estimated Times (weeks) 2-2-3 2-3-6 3-4-5 4-5-8 H F G B I Immediate Activity Predecessor J K C M N O E End A F B I J C M N H, G, K, O 2-3-5 3-4-8 5-7-9 Estimated Times (weeks) 2-2-3 2-3-6 3-4-5 4-5-8 5-8-12 1-1-1 6-7-11 8-9-13 a. Construct a network diagram. You can use either AOA or AON (see Example 5). b. If the project is finished within 26 weeks of its start, the project manager will receive bonus of $1,000; and if the project is finished within 27 weeks of its start, the bonus will be $500. Find the probability of each bonus. Page 5675 SWNT 1 Problem 12 2 3 Given: 4 8 9 one au 5 5 口 18 19 2017 B4 25 257 28 29 30 1 2 3 34 35 35 勐8鹞042□ 鹌 5 5D 8 9 50 512 10 11 12 13 14 15 16 17 22 23 24 26 29 Path A-D-E-H 36 Path 2 37 25 a. construct a network diagram 38 39 41 43 Path 3 44 45 46 Given: We are given the following times (optimistic, most likely, and pessimistic) for each activity in the table below. Activity Optimistic A 2 D 6 E 47 48 H F 49 G 30 Expected completion time=4+8+9.17+3.17 = 24.34 31 Variance 16/36+16/36 +25/36+9/36 =66/36 32 Standard deviation v66/36 = 1.354 33 z 26-24.34/1.354 1.23 50 Path 4 B I J K C Ready M N 27 b. Project manager will receive a bonus of $1,000 if the project is finished within 26 weeks Path T ≤ 26: 28 There are 4 paths so repeat for each path (use you network diagram) 0 End 7 2 3 5 2 2 3 4 5 1 6 8 34 Using Appendix B: Probability of completion s 26 weeks = 0.8907 Most Likely 4 8 9 3 4 7 2 3 4 5 8 1 7 9 ressimisu Chapter 17 Prob 1 6 10 12 5 8 9 3 6 5 8 12 1 11 13 Mean 4 8 9.17 3.17 4.5 7 2.17 3.33 4 5.33 8.17 1 75 9.5 Variance 16/36 16/36 25/36 936 25/36 16/36 136 16/36 436 16/36 49/36 0/36 25/36 25/36 Chapter 17 Prob 8 Table B.2 Chapter 17 12 Chapter 18 Prob 1 IV Cha 68 vi c ci đi thi cô là co gi 8 cô có cô ở cô Lô Lô 8 SRKERERRE S có có cô có cô có có cơ sở đã ô ô đồ côi c To 47 48 49 50 Path 4 51 52 53 54 55 56 57 Conclusion Probability of receiving a bonus of $1,000= Probability (0.8907 X Path 2 X Path 3 X Path 4) = 58 59 60 b-2. Project manager will receive a bonus of $500 if the project is finished within 27 weeks Path T ≤ 27: 61 There are 4 paths so repeat for each path (use you network diagram) Path A-D-E-H 62 63 Expected completion time=4+8+9.17+3.17 24.34 64 Variance = 16/36 + 16/36 +25/36+9/36-66/36 65 Standard deviation v66/36 = 1.354 66 z=27-24.34/1.354 = 1.96 Using Appendix B: Probability of completion s 27 weeks = 0.9750 67 68 69 Path 2 70 71 72 73 74 75 76 Path 3 77 78 79 80 81 82 83 Path 4 84 85 86 87 88 89 90 Conclusion Probability of receiving a bonus of $1,000= Probability (0.9750 X Path 2 X Path 3 X Path 4) = 91 92 93 94 95 96 97 98 Remember if the z value> +3.00 treat the prbability of completion as being = 1.0000 Ready Chapter 17 Prob 1 Chapter 17 Prob 8 Chapter 17 12 Chapter 18 Prob 1 12. A project manager has compiled a list of major activities that will be required to install a computer information system in her firm. The list includes estimated completion times for activities and precedence relationships. Immediate Activity Predecessor A D E H F G B I J A K D Immediate Activity Predecessor E A F B I J Estimated Times (weeks) 2-4-6 6-8-10 7-9-12 2-3-5 3-4-8 5-7-9 Estimated Times (weeks) 2-2-3 2-3-6 3-4-5 4-5-8 H F G B I Immediate Activity Predecessor J K C M N O E End A F B I J C M N H, G, K, O 2-3-5 3-4-8 5-7-9 Estimated Times (weeks) 2-2-3 2-3-6 3-4-5 4-5-8 5-8-12 1-1-1 6-7-11 8-9-13 a. Construct a network diagram. You can use either AOA or AON (see Example 5). b. If the project is finished within 26 weeks of its start, the project manager will receive bonus of $1,000; and if the project is finished within 27 weeks of its start, the bonus will be $500. Find the probability of each bonus. Page 5675 SWNT 1 Problem 12 2 3 Given: 4 8 9 one au 5 5 口 18 19 2017 B4 25 257 28 29 30 1 2 3 34 35 35 勐8鹞042□ 鹌 5 5D 8 9 50 512 10 11 12 13 14 15 16 17 22 23 24 26 29 Path A-D-E-H 36 Path 2 37 25 a. construct a network diagram 38 39 41 43 Path 3 44 45 46 Given: We are given the following times (optimistic, most likely, and pessimistic) for each activity in the table below. Activity Optimistic A 2 D 6 E 47 48 H F 49 G 30 Expected completion time=4+8+9.17+3.17 = 24.34 31 Variance 16/36+16/36 +25/36+9/36 =66/36 32 Standard deviation v66/36 = 1.354 33 z 26-24.34/1.354 1.23 50 Path 4 B I J K C Ready M N 27 b. Project manager will receive a bonus of $1,000 if the project is finished within 26 weeks Path T ≤ 26: 28 There are 4 paths so repeat for each path (use you network diagram) 0 End 7 2 3 5 2 2 3 4 5 1 6 8 34 Using Appendix B: Probability of completion s 26 weeks = 0.8907 Most Likely 4 8 9 3 4 7 2 3 4 5 8 1 7 9 ressimisu Chapter 17 Prob 1 6 10 12 5 8 9 3 6 5 8 12 1 11 13 Mean 4 8 9.17 3.17 4.5 7 2.17 3.33 4 5.33 8.17 1 75 9.5 Variance 16/36 16/36 25/36 936 25/36 16/36 136 16/36 436 16/36 49/36 0/36 25/36 25/36 Chapter 17 Prob 8 Table B.2 Chapter 17 12 Chapter 18 Prob 1 IV Cha 68 vi c ci đi thi cô là co gi 8 cô có cô ở cô Lô Lô 8 SRKERERRE S có có cô có cô có có cơ sở đã ô ô đồ côi c To 47 48 49 50 Path 4 51 52 53 54 55 56 57 Conclusion Probability of receiving a bonus of $1,000= Probability (0.8907 X Path 2 X Path 3 X Path 4) = 58 59 60 b-2. Project manager will receive a bonus of $500 if the project is finished within 27 weeks Path T ≤ 27: 61 There are 4 paths so repeat for each path (use you network diagram) Path A-D-E-H 62 63 Expected completion time=4+8+9.17+3.17 24.34 64 Variance = 16/36 + 16/36 +25/36+9/36-66/36 65 Standard deviation v66/36 = 1.354 66 z=27-24.34/1.354 = 1.96 Using Appendix B: Probability of completion s 27 weeks = 0.9750 67 68 69 Path 2 70 71 72 73 74 75 76 Path 3 77 78 79 80 81 82 83 Path 4 84 85 86 87 88 89 90 Conclusion Probability of receiving a bonus of $1,000= Probability (0.9750 X Path 2 X Path 3 X Path 4) = 91 92 93 94 95 96 97 98 Remember if the z value> +3.00 treat the prbability of completion as being = 1.0000 Ready Chapter 17 Prob 1 Chapter 17 Prob 8 Chapter 17 12 Chapter 18 Prob 1

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Introduction Jared diamond basic theory is that some cou... View the full answer