A conveyor belt drier is used to dry fermented tea from 60% moisture content to 5%...

 

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A conveyor belt drier is used to dry fermented tea from 60% moisture content to 5% (wet basis). Dry hot air from the furnace enters the dryer at 110 C with a 1% RH. The drying air leaves the drier at 30 C at 70% RH. For this purpose 150 kg dry air/ kg solid tea is used at steady state conditions. Suddenly at t= 0, the flow rate of drying air is increased to 200 kg dry air/kg solid tea; a) Calculate K and t? b) What will be the response equation of the output variable, y(t)=? c) What will be the water content of tea leaves at 30. minute? A conveyor belt drier is used to dry fermented tea from 60% moisture content to 5% (wet basis). Dry hot air from the furnace enters the dryer at 110 C with a 1% RH. The drying air leaves the drier at 30 C at 70% RH. For this purpose 150 kg dry air/ kg solid tea is used at steady state conditions. Suddenly at t= 0, the flow rate of drying air is increased to 200 kg dry air/kg solid tea; a) Calculate K and t? b) What will be the response equation of the output variable, y(t)=? c) What will be the water content of tea leaves at 30. minute?

Answer rating: 100% (QA)

To solve this problem we can use the drying rate equation and the mass balance for moisture content ... View the full answer