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•  a) Draw a force diagram for each block. Be sure to label the agents causing each force.
• b) Using a proper coordinate system to represent your x and y axes, write the proper expressions for Newton's Second Law for each mass. 
•  c) Find the tension, T, in the string holding the top block in place.
•  d) Find the acceleration of the bottom block.

Transcribed Image Text:

An 6 kg block is placed on top of a 11 kg block. A horizontal force of 138 N is applied to the 11 kg block while the 6 kg block is tied to the wall. The coefficient of friction between the floor and the bottom block as well as the two blocks themselves is μ = 0.27. 6 kg 11 kg F-138 N An 6 kg block is placed on top of a 11 kg block. A horizontal force of 138 N is applied to the 11 kg block while the 6 kg block is tied to the wall. The coefficient of friction between the floor and the bottom block as well as the two blocks themselves is μ = 0.27. 6 kg 11 kg F-138 N