(a) Find the time when the stone reaches its maximum height. Write the velocity and position...

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(a) Find the time when the stone reaches its maximum height. Write the velocity and position kinematic equations. Substitute a = -9.80 m/s2, vo = 24.2 m/s, and yo = 0 into the preceding two equations. Substitute v = 0, the velocity at maximum height, into Equation (1) and solve for time. v = at + Vo Ay = y - Yo = vot + ½ at² v = (-9.80 m/s2)t + 24.2 m/s (1) y = (24.2 m/s)t - (4.90 m/s²)t2 (2) 0 = (-9.80 m/s²)t + 20.0 m/s -24.2m/s -9.80m/s² t = (a) Find the time when the stone reaches its maximum height. Write the velocity and position kinematic equations. Substitute a = -9.80 m/s2, vo = 24.2 m/s, and yo = 0 into the preceding two equations. Substitute v = 0, the velocity at maximum height, into Equation (1) and solve for time. v = at + Vo Ay = y - Yo = vot + ½ at² v = (-9.80 m/s2)t + 24.2 m/s (1) y = (24.2 m/s)t - (4.90 m/s²)t2 (2) 0 = (-9.80 m/s²)t + 20.0 m/s -24.2m/s -9.80m/s² t =

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To find time t when the stone reaches maximum height Hence so... View the full answer