A heat engine and a refrigerator are tied together, so that all the work produced by...
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A heat engine and a refrigerator are tied together, so that all the work produced by the engine is used to power the refrigerator. Both devices operate between the same temperature limits. The heat engine has an efficiency of 0.5 and receives 100 kJ of heat from the high temperature reservoir. Calculate a) Wnet and Qu for the heat engine. (2 points) If 50k] of refrigeration is required, calculate. b) QH' and the COP for the refrigerator. (2 points) If the high temperature reservoir is at TH = 1000 K, determine c) The minimum possible TL (1 points) TH QHYWnet, (HE) QL TL QH (R) QL Qu= 100kJ Q = 50kJ MHE = 0.5 не TH = 1000 K A heat engine and a refrigerator are tied together, so that all the work produced by the engine is used to power the refrigerator. Both devices operate between the same temperature limits. The heat engine has an efficiency of 0.5 and receives 100 kJ of heat from the high temperature reservoir. Calculate a) Wnet and Qu for the heat engine. (2 points) If 50k] of refrigeration is required, calculate. b) QH' and the COP for the refrigerator. (2 points) If the high temperature reservoir is at TH = 1000 K, determine c) The minimum possible TL (1 points) TH QHYWnet, (HE) QL TL QH (R) QL Qu= 100kJ Q = 50kJ MHE = 0.5 не TH = 1000 K
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Answer rating: 100% (QA)
SOLUTION a For the heat engine Efficiency Work out Heat in 05 Heat in QH 100 kJ Work out Wnet Efficiency x Heat in 05 x 100 kJ 50 kJ Heat rejected Qc ... View the full answer
Related Book For
Introduction to Chemical Engineering Thermodynamics
ISBN: 978-0071247085
7th edition
Authors: J. M. Smith, H. C. Van Ness, M. M. Abbott
Posted Date:
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