A horizontal well can be considered composed of 3 straight segments: a vertical section of 4,000...

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A horizontal well can be considered composed of 3 straight segments: a vertical section of 4,000 ft, an inclined section (at 60 deg) of 7,000 ft, and a horizontal section of 3,000 ft. A Power-Law fluid is pumped with a pump pressure of 3,000 psi. Your boss wants to know the dynamic (circulating) bottomhole pressure at the current measured depth of 14,000 ft. The drill string is composed of DP + DC as follows: Given: Component DC DP Last Casing shoe depth Last Casing ID Bit size Determine: The friction losses inside the surface lines are 100 psi. The friction losses inside the drill string and in the annulus can be computed using API RP 13D. Unfortunately, nobody remembers what the jet sizes in the bit are. Mud data Flowrate Mud density Fann reading @ 600 rpm Fann reading @ 300 rpm Fann reading @ 100 rpm Fann reading @ 3 rpm 7,500 8.681 8.5 OD 6" 5" 400 11 80 51 24 6 ft TVD in. in. ID 2 " 4.276" gpm ppg Length 1,000 ft 13,000 ft a) TFA at the bit. Consider Cd = 0.95. b) ECD at bottom c) ECD at shoe (direct circulation: down DS, up annulus) d) ECD at shoe (reverse circulation: down annulus, up DS) A horizontal well can be considered composed of 3 straight segments: a vertical section of 4,000 ft, an inclined section (at 60 deg) of 7,000 ft, and a horizontal section of 3,000 ft. A Power-Law fluid is pumped with a pump pressure of 3,000 psi. Your boss wants to know the dynamic (circulating) bottomhole pressure at the current measured depth of 14,000 ft. The drill string is composed of DP + DC as follows: Given: Component DC DP Last Casing shoe depth Last Casing ID Bit size Determine: The friction losses inside the surface lines are 100 psi. The friction losses inside the drill string and in the annulus can be computed using API RP 13D. Unfortunately, nobody remembers what the jet sizes in the bit are. Mud data Flowrate Mud density Fann reading @ 600 rpm Fann reading @ 300 rpm Fann reading @ 100 rpm Fann reading @ 3 rpm 7,500 8.681 8.5 OD 6" 5" 400 11 80 51 24 6 ft TVD in. in. ID 2 " 4.276" gpm ppg Length 1,000 ft 13,000 ft a) TFA at the bit. Consider Cd = 0.95. b) ECD at bottom c) ECD at shoe (direct circulation: down DS, up annulus) d) ECD at shoe (reverse circulation: down annulus, up DS)