A particle moving along the x axis in simple harmonic motion starts from its equilibrium position,...

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A particle moving along the x axis in simple harmonic motion starts from its equilibrium position, the origin, at t= 0 and moves to the right. The amplitude of its motion is 1.70 cm, and the frequency is 1.70 Hz. (a) Find an expression for the position of the particle as a function of time. (Use the following as necessary: t. Assume that x is in centimeters and t is in seconds. Do not include units in your answer.) x = 1.70 sin (3.4nt) (b) Determine the maximum speed of the particle. A particle moving along the x axis in simple harmonic motion starts from its equilibrium position, the origin, at t= 0 and moves to the right. The amplitude of its motion is 1.70 cm, and the frequency is 1.70 Hz. (a) Find an expression for the position of the particle as a function of time. (Use the following as necessary: t. Assume that x is in centimeters and t is in seconds. Do not include units in your answer.) x = 1.70 sin (3.4nt) (b) Determine the maximum speed of the particle.

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To determine the maximum speed of a particle in simple harmonic motion SHM we can use the equation o... View the full answer