A particles velocity in meters per second along the x$-$axis is described by v$($x$)=$Ax$+$Bx$2$v$($x$)=$Ax$+$Bx$2,$ where the position xx is in meters. The values of the constants are A $=6\mathrm{.}47,$ and B $=-4\mathrm{.}1.$ a$)$at what position in meters are the particels have a velocity of $0$ besides the orgin

B$)$what is the acelleration in meters per second squared of at particle at x$1=1\mathrm{.}24$m

C$)$what is the acelleration in meters per second of the particle you found in part b

Answer rating: 100% (QA)

Particle Motion Analysis Were given that the particles velocity is described by vx Ax Bx2 where A 64... View the full answer